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The treatment of endothermic reactions near the threshold

At low incident energies the angular distribution of secondary particles is isotropic (with p(E1,$ \eta$) = 1/2), so that the integral in (11) vanishes, and we have

$\displaystyle \langle$Ex$\displaystyle \rangle$ = ($\displaystyle \alpha$ + $\displaystyle \gamma$)E1 + $\displaystyle \beta$Q. (12)
For endothermic reactions (Q < 0) and for E1 near the threshold, the arithmetic on the right-hand side of this equation may lead to the subtraction of nearly equal numbers. In this circumstance we therefore modify the calculation of $ \langle$Ex$ \rangle$ as follows.

We begin by computing the threshold, which occurs when the secondary particles have zero energy in the center-of-mass system. Thus, we set Ex' = 0 and Ey' = 0 in (7) to get that the threshold is when

E1' + E2' = - Q.

In terms of laboratory coordinates with a stationary target (v2 = 0), this equation takes the form

E1 - $\displaystyle {\frac{{1}}{{2}}}$(m1 + m2)V02 = - Q.

We may now use (3) to write the velocity V0 of the center of mass in terms of v1 to get that the threshold occurs when the incident energy E1 is equal to Ethreshold with Ethreshold given by

Ethreshold = - $\displaystyle \left(\vphantom{
\frac{m_1 + m_2} {m_2}
}\right.$$\displaystyle {\frac{{m_1 + m_2}}{{m_2}}}$$\displaystyle \left.\vphantom{
\frac{m_1 + m_2} {m_2}
}\right)$Q. (13)

In laboratory coordinates at threshold the secondary particles are both moving at the velocity of the center of mass. The energy Ex is therefore equal to

Ex = $\displaystyle {\frac{{1}}{{2}}}$mxV02.

By (3) this is equal to

Ex = $\displaystyle {\frac{{m_1 m_x}}{{(m_1 + m_2)^2}}}$E1,

and at the threshold E1 = Ethreshold we find from (13) that

Ex = - $\displaystyle {\frac{{m_1 m_x}}{{m_2 (m_1 + m_2)}}}$Q. (14)

On the basis of these ideas, for an endothernmic reaction when the incident particle is near threshold and the angular distribution is isotropic, we calculate $ \langle$Ex$ \rangle$ by using the formula

$\displaystyle \langle$Ex$\displaystyle \rangle$ = ($\displaystyle \alpha$ + $\displaystyle \gamma$)(E1 - Ethreshold) - $\displaystyle {\frac{{m_1 m_x}}{{m_2 (m_1 + m_2)}}}$Q. (15)
It is easy to show that the two equations, (15) and (12), are mathematically equivalent. From the point of view of computer arithmetic, however, (15) is much more reliable.
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Next: Continuum two-body reactions Up: Discrete two-body reactions Previous: Discrete two-body reactions